Question 402135
A man is 3 times as old as his daughter. 
4 years ago, the sum of their ages was 60 years. 
How old is the daughter?
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Equations:
f = 3d
(f-4)+(d-4) = 60
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Substitute for "f" and solve for "d":
(3d-4)+(d-4) = 60
4d-8 = 60
4d = 68
d = 17 (daughter's age now)
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Solve for "f":
f = 3d
f = 3*17 = 51 (father's age now)
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Cheers,
Stan H.
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