Question 401948

given:

{{{b1=10in}}} 
{{{b2=14in}}} and 
the altitude {{{h=16in}}}


{{{A= (1/2)(b1+b2)h}}}


{{{A= (1/2)(10in+14in)16in}}}


{{{A= (1/2)(24in)16in}}}


{{{A= (1/cross(2))(24in)cross(16)8in}}}


{{{A= (24in)8in}}}


{{{A= 192in^2}}}