Question 43412
write in polar form: 2sqroot2(1-i)
SEE THE FOLLOWING AND TRY.IF STILL IN DIFFICULTY PLEASE COME BACK
write in polar form: negative sqroot of 5+i
Z=5+I
|Z|=R=SQRT(5^2+1^2)=SQRT(26)
TAN(THETA)=1/5.....THETA=TAN^-1 (1/5)=A SAY
Z=R*E^(iA)={(26)^0.5}*{E^(iA)}
-SQRT(Z)=-{(26)^0.25}*E^(iA/2)=-2.258*E^(0.1974i)....ANGLE IN RADIANS ..OR...
=-2.258*E^(11.316i)....ANGLE IN DEGREES