Question 43415
r = sqrt(x^2 + y^2)
theta = arctan(y/x) ...I use q for theta
so that
r = sqrt(5 + 1) = sqrt(6)
q = arctan(1/-sqrt(5))
and thus in polar form we have
(sqrt(6), arctan(1/-sqrt(5)) or about
(2.449, -24.1°)