<PRE><B>Question 401654</B>
The second angle of a triangular garden is four times as large as the first. The third angle is 45 degrees less than the sum or the other two angles. Find the measure of each angle.
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A = 1st angle, B = 2nd, C = 3rd
B = 4A
C = A + B -45 = A + 4A + 45 = 5A + 45
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A + 4A + 5A+45 = 180
10A = 135º
Can you finish it?
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