Question 401637
1)  {{{(1/8)int(int((6-x-y), dx, 0,1), dy, 2,3) = (1/8)int((11/2 - y), dy, 2,3) = (1/8)*(11y/2 - y^2/2)[2]^3 = 3/8}}}.


2)   {{{(1/8)int(int((6-x-y), dx, 0,3-y), dy, 2,3) = (1/8)int((27/2 - 6y+y^2/2), dy, 2,3) = (1/8)*(27y/2 - 3y^2 +y^3/6) [2]^3 = 5/24}}}