<PRE><B>Question 401569</B>
for m: {{{(3)/(m^2)}}}={{{(m-4)/(3m^2)}}}+{{{(2)/(3m^2)}}}
the common denominator is 3m^2, multiply by that
3m^2*{{{(3)/(m^2)}}}= 3m^2*{{{(m-4)/(3m^2)}}}+ 3m^2*{{{(2)/(3m^2)}}}
:
cancel the denominators and you have:
3(3) = (m-4) + 2
9 = m - 2
9 + 2 = m
m = 11
:
:
Check this in the original problem, replace m with 11:
{{{(3)/(11^2)}}}={{{(11-4)/(3(11^2))}}}+{{{(2)/(3(11^2))}}} = {{{(3)/(121)}}}={{{(7)/(363)}}}+{{{(2)/(363)}}}
{{{(9)/(363)}}} reduces to {{{3/121}}}</PRE>