Question 401571


four consecutive even integers
{{{n}}}, 
{{{(n + 2)}}}, 
{{{(n + 4)}}} and 
{{{(n + 6)}}}


 {{{twice}}} the {{{sum}}} of the {{{second}}} and {{{third}}}:

{{{2((n + 2)+(n + 4))=2(2n+6)=4n+12}}}

exceeds 3 times ,{{{3n}}} the first by {{{34}}}

or

{{{4n+12=3n+34}}}

{{{4n+12-3n=3n-3n+34}}}


{{{n+12-12=34-12}}}

{{{n=22}}}....first number

{{{n + 2=22+2=24}}}, .....second

{{{n + 4=22+4=26}}} .......third 
and 
{{{n + 6=22+6=28}}}..........fourth


check:

twice the sum of the second and third: {{{2(24+26)=2*50=100}}}

3 times the first: {{{3n=3*22=66}}}

exceeds by: {{{100-66=34}}}