Question 401485
{{{r+5/r=-6}}}
{{{r^2+5=-6r}}}
{{{r^2+6r+5=0}}} quadratic equation
 {{{r = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
 {{{r = (-6 +- sqrt( 6^2-4*1*5 ))/(2*1) }}} 
 {{{r = (-6 + sqrt(16))/2 }}} or  {{{r = (-6 - sqrt(16))/2 }}} 
 {{{r = (-6 + 4)/2 }}} or  {{{r = (-6 - 4)/2 }}}
 {{{r = (-2)/2 }}} or  {{{r = (-10)/2 }}}
 {{{r = -1 }}} or  {{{r = -5}}}