Question 401473

{{{(2a^3x^-2/y^-1b^2)^3(y^2a^-4/8bx^5)^-1}}}


{{{(2a^3(1/x^2)/(1/y)b^2)^3(1/(y^2(1/a^4)/8bx^5))}}}



{{{((2a^3y)/x^2b^2)^3(8bx^5a^4/y^2))}}}


{{{((2^3a^9y^3)/x^6b^6)(8bx^5a^4/y^2))}}}


{{{((8a^9y^3)(8bx^5a^4))/(x^6b^6)y^2))}}}


{{{((8a^9y^cross(3))(8cross(b)(cross(x^5))a^4))/(x^cross(6)b^cross(6)5)cross(y^2)))}}}



{{{((64a^13y)/(xb^5)))}}}


this proves that your answer is correct!