Question 401376

a)  here one ball of each color 
   
 no. of ways = 5C1 * 4C1 * 3C1 = 60


b)     no. of ways = 5C3 = 10


c) no. of ways = 4C2 * 3C1 = 6 * 3 = 18 


d) number of non-blue ball = 8 

 no. of ways = 8C3 = 56