Question 401369
{{{sqrt(20)*sqrt(40)}}} = {{{sqrt(800)}}}
therefore, 
 {{{sqrt(800)}}}= {{{sqrt(100*8)}}}  "factoring"
          = {{{sqrt(100*4*2)}}} "further factoring of 8 (4*2)"
then = {{{10*2*sqrt(2)}}} "the squares of {{{sqrt(100)}}} and {{{sqrt(4)}}} gives 10 and 2"
     = {{{20*sqrt(2)}}}

Hence factoring {{{sqrt(20)*sqrt(40)}}}will give {{{20*sqrt(2)}}}.