Question 401362
A RECTANGLE IS 16M BY9M.FIND A SIDE OF THE SQUARE WHOSE AREA EQUALS THE AREA OF THE RECTANGLE. BY HOW MUCH DOES THE PERIMETER OF THE RECTANGLE EXCEED THE PERIMETER OF THE SQUARE.
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Area of rectangle = 16*9= 144 m^2
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Area of square = L^2 = 144
L= 12 m
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Perimeter of rectangle = 2*(L+W) ===>2*(16+9)
Perimeter = 50 m
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Perimeter of square = 4*L = 48 m
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Difference = 2 m 
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