Question 401332
{{{ 1/(x+3) - 1/(x+4) = 1/2}}}
==> {{{2((x+4)-(x+3))=(x+3)(x+4)}}}
==> {{{2 = x^2 + 7x + 12}}}
==> {{{0 = x^2 + 7x + 10}}}
<==> 0 = (x + 2)(x+ 5) ==> x = -2, -5.
Both values will never make the denominator 0, so they are the final answers.