Question 43368
You are wrong!


{{{x^2 + 2x + y^2 - 10y + 22 = 0}}}
or {{{(x^2 + 2*x*1 + 1^2) + (y^2 - 2*y*5 + 5^2) + 22 - 1^2 -5^2 = 0}}}
or {{{(x+1)^2 + (y-5)^2 + 22 - 1 - 25 = 0}}}
or {{{(x+1)^2 + (y-5)^2 - 4 = 0}}}
or {{{(x+1)^2 + (y-5)^2 = 4}}}
or {{{(x+1)^2 + (y-5)^2 = 2^2}}}


So the given equation represents a circle with centre at (-1,5) and radius 2 units.