Question 401199
If the first integer is {{{x}}}
The second integer is 3 more than the first, then the second integer is {{{(x+3)}}}
The third integer is 1 more than twice the first, twice the first is {{{2x}}}, then the thitd integer is {{{(2x+1)}}}
The sum of three integers is {{{x+(x+3)+(2x+1)}}}
From text the sum of three integers is 52
equation 
{{{x+(x+3)+(2x+1)=52}}}
{{{x+x+3+2x+1=52}}}
{{{4x=52-1-3}}}
{{{4x=48}}}
{{{x=48/4}}}
{{{x=12}}} the first integer
then the second is {{{(x+3)=12+3=15}}}
the third integer is {{{(2x+1)=2*12+1=25}}}
Answer: 12; 15; 25