Question 401182
Gardening: a homeowner designs a rectangular garden such that the length is 20 feet more than twice the width. if 310 feet of picket fencing are to be used, find the length and width of the garden?
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Let w = width
then
2w+20 = length
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"perimeter of garden" = "amount of fencing"
2(w + 2w+20) = 310
2(3w+20) = 310
3w+20 = 155
3w = 135
w = 45 feet (width)
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Length:
2w+20 = 2(45)+20 = 90+20 = 110 feet