Question 401187
Let {{{s}}} = the speed of the slower bus
Let {{{d}}} = the distance the slower bus travels
{{{s + 5}}} = the speed of the faster bus
{{{375 - d}}} = distance the faster bus travels
{{{3}}} hrs = time for both buses
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slower bus:
(1) {{{ d = s*3}}}
faster bus:
(2) {{{375 - d = (s + 5)*3}}}
From (1):
(1) {{{s = d/3}}}
Substitute (1) into (2):
(2) {{{375 - d = (d/3 + 5)*3}}}
(2) {{{375 - d = d + 15}}}
(2) {{{2d = 360}}}
{{{d = 180}}}
{{{375 - d = 195}}}
The slower bus went 180 mi and the faster bus went 195 mi
check answer:
(1) {{{ 180 = s*3}}}
(1) {{{s = 60}}}
(2) {{{375 - 180 = (s + 5)*3}}} 
(2) {{{195 = 3s + 15}}}
(2) {{{3s = 180}}}
(2) {{{s = 60}}}
OK