Question 400837
you can think of 1 standing still and the
other moving at the sum of their speeds
{{{60 = (r+ 2r)*2}}}
{{{60 = 6r}}}
{{{r  10}}} mi/hr
{{{2r = 20}}} mi/hr
The speed of the faster cyclist was 20 mi/hr
check answer:
slower cyclist:
{{{d[1] = 10*2}}}
{{{d[1] = 20}}} mi
faster cyclist:
{{{d[2] = 20*2}}}
{{{d[2] = 40}}} mi
{{{20 + 40 = 60}}}
OK