Question 5528
Factor by grouping:
{{{(q^3-q^2)+(2q-2)}}}
factor out {{{q^2}}} from the first group and 2 from the second group:
{{{q^2(q-1)+2(q-1)}}}
then factor out (q-1) from the equation:
{{{(q-1)(q^2+2)}}}
nothing else can be factored, so this is the answer.