Question 400576
{{{x + abs(y) = 3}}}
{{{abs(y) = 3 - x}}}
Since the left side can never be negative, then the
right side can be zero, but never negative
{{{0 <= 3 - x}}}
Add {{{x}}} to both sides
{{{x <= 3}}}
This makes sense, because if {{{ x>3 }}}, then
{{{x + abs(y) = 3}}} can never be true
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Also,
{{{x = 3 - abs(y)}}}
This is the sum of
{{{x = 3}}} and
{{{x = abs(y)}}}
This is not really a function, because there is a (+) and (-) value
of {{{y}}} for each {{{x}}}, so its the sum of 2 functions
{{{x = abs(y)}}} and
{{{x = abs(-y)}}}
Include the restriction {{{x <= 3}}}
I hope this helps, I don't have the tools to graph, but
you should be able to draw it.