Question 400526
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The number: *[tex \Large x]


The opposite of the number:  *[tex \Large -x]


Increased by 5:  *[tex \Large -x\ +\ 5]


Doubled: *[tex \Large -2x\ +\ 10]


Added to twice the number: *[tex \Large -2x\ +\ 10\ +\ 2x]


The result is: *[tex \Large -2x\ +\ 10\ +\ 2x =]


Four more than the number: *[tex \Large -2x\ +\ 10\ +\ 2x =\ x\ +\ 4]


Just solve for *[tex \Large x]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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