Question 400020
you have ten six-sided dice in a cup. If you shake the cup, toss all 
of the dice on the table at one time, and count the number of threes, how many 
threes would you expect to see?
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Ans: (1/6)*10 = 10/6 = 5/3
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What percentage of the time would you expect to see an outcome of five 
threes?
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Binomial with n = 10 and p = 1/6
P(x=5) = 10C5(1/6)^5*(5/6)^5 = 0.013
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Cheers,
Stan H.
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