Question 400438
x + y = 2,
{{{3(1/x + 1/y) = 8}}}

==> {{{3((x+y)/(xy) )= 8}}}
==> {{{3(2/(xy)) = 8}}} ==> {{{3/(xy) = 4}}}
==> {{{xy = 3/4}}} ==> {{{x(2-x) = 3/4}}}
==> {{{8x - 4x^2  =3}}}
==> {{{0 = 4x^2 - 8x + 3}}}
==> 0 = (2x - 1)(2x - 3) ==> x = 1/2, 3/2.