Question 400178
Odd number we can write in this way {{{2*n-1}}} when n is integer
then consecutive odd number is  {{{2*(n+1)-1=2n+2-1=2n+1}}}
and the next even number (just next number after {{{2n+1}}}) is {{{(2n+1)+1=2n+1+1=2n+2}}}
the sum of two consecutive odd numbers plus the next even number is {{{(2n-1)+(2n+1)+(2n+2)=2n-1+2n+1+2n+2=6n+2}}}
From problem's text we know that  the sum of two consecutive odd numbers plus the next even number is 56
So equation is

{{{(2n-1)+(2n+1)+(2n+2)=56}}}
.
{{{6n+2=56}}}