Question 400142
{{{f(x)=(x-1)/x}}} g(x)={{{ sqrt(x+3)}}}
{{{f(g(x))=(g(x)-1)/g(x)=(sqrt(x+3)-1)/sqrt(x+3)}}} 
{{{f(f(g(x)))=(f(g(x))-1)/f(g(x))=(((sqrt(x+3)-1)/sqrt(x+3)) -1)/(((sqrt(x+3)-1)/sqrt(x+3)) )=((sqrt(x+3)-1)/sqrt(x+3) -sqrt(x+3)/sqrt(x+3))/(((sqrt(x+3)-1)/sqrt(x+3)) )=((sqrt(x+3)-1 -sqrt(x+3))/sqrt(x+3))*(sqrt(x+3)/(sqrt(x+3)-1) )=-1/(sqrt(x+3)-1)}}}