Question 400010
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Hi
solving system of linear equations through elimination
2x-y+z=1
x+y-7=2
3x-y+z=0

2x-y+z=1
3x-y+z=0

-2x +y -z=-1  |Mulitplying 1st equation by -1, prior to adding the equations
 3x -y +z=0
  x = -1
x+y-7=2   |Substituting x = -1 into an equation to solve for y
-1 + y = 9
  y = 10
3x-y+z=0  |Substituting x = -1 and y = 10 into an equation to solve for z
 -3 -10 + z = 0
        z = 13
CHECKING our Answer***
2x - y + z =1
 -2 -10 + 13 = 1