Question 400018
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Let *[tex \Large x] represent the number of quarters.  Then *[tex \Large 25x] is the value of those quarters in cents.  Since there are 33 less nickels than quarters, *[tex \Large x\ -\ 33] must represent the number of nickels.  *[tex \Large 5(x\ -\ 33)] then represents the value of the nickels in cents.  The value of the quarters plus the value of the nickels is $20.25, but that is the same as 2025 cents.  Therefore:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 25x\ +\ 5(x\ -\ 33)\ =\ 2025]


Solve for *[tex \Large x] to get the number of quarters.  Subtract 33 to find the number of nickels.


Oh, by the way:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 0.25x\ +\ 0.05(x\ -\ 33)\ =\ 20.25]


would work just as well.  It is just that I would rather work with integer coefficients given the choice.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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