Question 399994
{{{16^(-3/4)}}}
The general rule is
{{{a^(-b) = 1/(a^b)}}}, so
{{{16^(-3/4) = 1/(16^(3/4))}}}
This is the same as
{{{1/((root(4,16))^3)}}}
This  equals
{{{1/(2^3) = 1/8}}} answer