Question 399942
<pre>

I didn't think you meant x as a base.  The x's then just cancel out,
and you get the same thing as the other tutors got, except to base 10
and not base x.  


{{{2*log((xy^(1/3))) + log((xy^2)) - 3*log((xy))}}}

{{{log(((xy^(1/3))^2)) + log((xy^2)) - log(((xy)^3))}}}

{{{log((x^2y^(2/3))) + log((xy^2)) - log((x^3y^3))}}}

{{{log((x^2y^(2/3)xy^2)) - log((x^3y^3))}}}

{{{log((x^3y^(2&2/3))) - log((x^3y^3))}}}

{{{log((x^3y^(8/3))) - log((x^3y^3))}}}

{{{log(((x^3y^(8/3))/(x^3y^3)))}}}

{{{log((  "1/"(y^(3-8/3)  )))}}} ignore the dot.  It's "one over"

{{{log((  "1/"(y^(9/3-8/3)  )))}}}

{{{log((  "1/"(y^(1/3)  )))}}}

Edwin</pre>