Question 399942
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Hi
*[tex \LARGE\ \ log_bx + log_by = log_b(xy) ]
*[tex \LARGE\ \ log_bx - log_by = log_b(x/y) ]

2logxy^1/3 + logxy^2 - 3logxy
 logx y^2/3 + logx y^2 - logx y^3
 logx (y^8/3)/y^3 
  logx y^(-1/3)