Question 399667
{{{3x+2y=10}}}
{{{2x+3y=10}}}
Slove this problem using substitution
From the first equation express y: 
{{{3x+2y=10}}}, {{{2y=10-3x}}}, {{{y=(10-3x)/2}}}, {{{y=10/2-(3x)/2}}}, {{{y=5-(3x)/2}}}
substitute {{{y=5-(3x)/2}}} in the second equation {{{2x+3y=10}}}
{{{2x+3*(5-(3x)/2)=10}}}
{{{2x+15-(9x)/2=10}}}
{{{2x-(9x)/2=10-15}}}
{{{(4x-9x)/2=-5}}}
{{{(-5x)/2=-5}}}
{{{x=(-5)/(-5/2)}}}
{{{x=2}}}
Put {{{x=2}}} in {{{y=5-(3x)/2}}}
{{{y=5-(3*2)/2}}}
{{{y=5-3}}}
{{{y=2}}}
Answer x=2,y=2