Question 399582
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Let *[tex \Large x] represent the smaller number.  Then *[tex \Large 2x\ +\ 4] must be the larger number. Then:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ 2x\ +\ 4\ =\ 70]


Solve for *[tex \Large x].


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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