Question 399376
g(x)=(x-3)^-4
Write it
y = (x-3)^-4
We can get rid of the neg exponent by using the reciprocal
y = {{{1/((x-3)^4)}}}
You can see as the value approaches x=3, the value of y will increase tremendously. 
We know y will be positive, an even numbered exponent takes care of that
Choose values for x: 
x = 1
y = {{{1/((1-3)^4)}}}
y = {{{1/((-2^4))}}}
y = {{{1/16}}}
Graph points 1, 1/16
x = 2 
y = {{{1/((2-3)^4)}}}
y = {{{1/((-1^4))}}}
y = 1
Graph points 2, 1
x = 2.5
y = {{{1/((2.5-3)^4)}}}
y = {{{1/((-.5^4))}}}
y = {{{1/.0625}}}
y = 16
Graph points 2.5, 16
Skip x=3, division by 0, the graph will have a hole there
x=3.5
y = {{{1/((3.5-3)^4)}}}
y = {{{1/((.5^4))}}}
y = {{{1/.0625}}}
Graph points 3.5, 16 
x=4
y = {{{1/((4-3)^4)}}}
y = {{{1/((1^4))}}}
y = {{{1/1}}}
y = 1
Graph points 4, 1

:
Looks something like this:
{{{ graph( 300, 200, -2, 5, -10, 30, (x-3)^-4) }}}