Question 399502
{{{(n^2 - 16)/(n+4)^2}}}
To remove factors of 1 we have to have factors. SO we start by factoring. The denominator is already factored. The numerator is a difference of squares:
{{{((n+4)(n-4))/((n+4)(n+4))}}}
We can see that the numerator and denominator have a common factor: (n+4). We can cancel this:
{{{(cross((n+4))(n-4))/(cross((n+4))(n+4))}}}
leaving:
{{{(n-4)/(n+4)}}}<br>
Note: Neither the n's nor the 4's cancel. They are not factors and only factors may be canceled.