Question 399436
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Hi
{{{x - sqrt(4x+45) = 0}}}
{{{x = sqrt(4x+45)}}}  |squaring both sides of the equation
  x^2 = 4x + 45
 x^2 - 4x - 45 = 0
factoring
 (x-9)(x+5) = 0
 (x+5)=0   x = -5  Extraneous solution  (-5 - sqrt(25) &#8800; 0)
 (x-9)=0   x = 9