Question 43248
In triangle ABC, c = 10 and angle A = angle B = 40o. Find the length of the median to line segment AC
let the median from B to AC be BE=M
AB=10...ANGLE A = ANGLE B =40...HENCE...AC=BC=X SAY...AND ANGLE C=180-40-40=100
10/SIN(100)=X/SIN(40)
X=10*SIN(40)/SIN(100)=6.523=AC=BC
IN TRANGLE BEC
EC=AC/2=3.262
BC=6.523
ANGLE BCE =100
BE^2=BC^2+CE^2-2*BC*CE*COS(BCE)=6.523^2+3.262^2-2*6.523*3.262*COS(100)
BE^2=60.538
BE=7.78