Question 399348
If one number is x
then other is (x+5)
their product is 54
so: {{{x*(x+5)=54}}}
{{{x^2+5x-54=0}}}
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
{{{x = (-5 + sqrt( 5^2-4*1*(-54) ))/(2*1) }}} or {{{x = (-5 - sqrt( 5^2-4*1*(-54) ))/(2*1) }}} 
{{{x = (-5 + sqrt( 241 ))/2 }}} or {{{x = (-5 -sqrt( 241 ))/2 }}}
so the first number is {{{x = (-5 + sqrt( 241 ))/2 }}} or {{{x = (-5 -sqrt( 241 ))/2 }}}
then the second number is {{{x+5 = (-5 -sqrt( 241 ))/2 }}} or {{{x +5= (-5 +sqrt( 241 ))/2 }}}
Answer: ({{{(-5 + sqrt( 241 ))/2}}} ,{{{(-5 -sqrt( 241 ))/2 }}}); ({{{(-5 -sqrt( 241 ))/2}}} ,{{{(-5 +sqrt( 241 ))/2 }}});