Question 399315
Let the integers be {{{m}}} and {{{n}}}
where {{{m}}} is the smaller
given:
(1) {{{m + n = 22}}}
(2) {{{8m = 2n + 56}}}
from (1):
{{{n = 22 - m}}}
Substituting:
{{{8m = 2*(22 - m) + 56}}}
{{{8m = 44 - 2m + 56}}}
{{{10m = 100}}}
{{{m = 10}}}
and, since
{{{m + n = 22}}}
{{{n = 12}}}
The numbers are 10 and 12