Question 399250
Write an equation in standard form of the line that has given slope and passes through the given point.
m=- 3/2 : (4, 2) 
:
Use the point/slope form: y - y1 = m(x - x1)
In this problem m =-3/2; x1=4; y1=2
:
y - 2 = {{{-3/2}}}(x - 4)
y - 2 = {{{-3/2}}}x - {{{-3/2}}}(4)
y - 2 = {{{-3/2}}}x + 6
y = {{{-3/2}}}x + 6 + 2
y = {{{-3/2}}}x + 8
Convert to standard (ax + by = c) form; multiply by 2 to get rid of the fraction
2y = -3x + 16
3x + 2y = 16 is the standard form
:
You can check the equation: substitute the given points, 4 for x, and 2 for y, 
3(4) + 2(2) = 16