Question 399213
2x+5k=6k^2-3kx-6 find X
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(2+3k)x = 6k^2-5k-6
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x = [6k^2-5k-6]/[3k+2]
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x = [6k^2-9k+4k-6]/[3k+2]
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x = [3k(2k-3)+2(2k-3)]/[3k+2]
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x = [(2k-3)(3k+2)]/[3k+2]
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x = 2k-3
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Cheers,
Stan H.
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