Question 43217
Okay from
x^(3/4) + 5/[x^(1/4)]
let us rationalize the denominator of the second fraction by multiplying top and bottom by x^(3/4)...notice that will make the new denominator a full x...so we get
x^(3/4) + 5*x^(3/4) / x^(3/4)*[x^(1/4)] =
x^(3/4) + 5*x^(3/4) / x
Now if you want to factor out the x^(3/4), we get
x^(3/4)[1 + 5/x]