Question 399214
From the co-vertices, {{{b^2  =2^2 = 4}}}.  Now {{{c^2 = 6^2 = 36}}}.
==> {{{b^2 = a^2 - c^2}}} ==> {{{4 = a^2 - 36}}}, or {{{a^2 = 40}}}.
The center of the ellipse is the origin (0,0).
Thus the equation of the ellipse is {{{x^2/4 + y^2/40  =1}}}