Question 399136
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If *[tex \Large y] varies inversely as *[tex \Large x], then you can say:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ \frac{k}{x}]


Which is all you can say unless you are given initial conditions *[tex \Large y_o] and *[tex \Large x_0].  Substitute the initial conditions and solve for *[tex \Large k]:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y_o\ =\ \frac{k}{x_o}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ k\ =\ x_oy_o]


After which you can use this value of *[tex \Large k] to solve for *[tex \Large y] given any value of *[tex \Large x]


Now, question for you.  Why are you so disrespectful to write "u" when you mean "you"?


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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