Question 399133
 The equation of the ellipse with vertices (a, 0), (-a, 0) and co-vertices (0, b), (0, -b) is
{{{x^2/a^2+y^2/b^2=1}}}
in this problem  the ellipse with vertices (6, 0), (-6, 0) and co-vertices (0, 2), (0, -2), so a=6, b=2
{{{x^2/6^2+y^2/2^2=1}}}
{{{x^2/36+y^2/4=1}}}- answer