Question 398983
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Hi
{{{(1/16)^(x+1)=(1/8)^(2x-1)}}}
{{{(1/2)^(4(x+1))=(1/2)^(3(2x-1))}}}
    4(x+1) = 3(2x-1)
   4x + 4 = 6x - 3
        7 = 2x
        7/2 = x