Question 43220
The position of the first bus at x hours (counting from the time the second bus departed) is:

{{{d[1] = 44x + 44}}}

The position of the second one is:

{{{d[2] = 54x}}}

We want to solve for how many hours (x), the following equation will be true:

{{{d[2]-d[1] = 274}}}

Since we used {{{d[1]}}} and {{{d[2]}}} only for clarity, let's substitute for the true formulas:

{{{54x - (44x + 44) = 274}}}
{{{10x - 44 = 274}}}

And we have a linear equation! Solving it we have:

*[invoke linear_equation "x", 10, -44, 274 ]

Verifying...

{{{54*(31.8) = 1717.2}}}
{{{44*(31.8) + 44 = 1443.2}}}
{{{1717 - 1443 = 274}}}

Therefore, that distance will happen at 31.8 hours after the second bus left (2 p.m or 14:00). Remember that 0.8 hours is {{{0.1*60*8}}} minutes, or 48. To get to 24:00 we need 10 hours, so it will happen at 31 - 10 = 21 hours and 48 minutes of the next day. A long time!