Question 398721
What is the equation of the tangent line to f(x)=x^2-2x+3/x-5 at (3,-3)?
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{{{f(x) = (x^2-2x+3)*(x-5)^-1}}}

The slope of f(x) = f'(x)
f'(x) = {{{(2x-2)/(x-5) - (x^2-2x+3)/(x-5)^2}}} 
f'(3) = -3.5
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m = -3.5 thru (3,-3)
y+3 = -3.5(x-3) = -3.5x + 10.5
7x + 2y = 15