Question 398673


given:

the line {{{3y-6x=1}}} and  point (-1,4)

{{{3y-6x=1}}}......write in slope-intercept form

{{{3y=6x+1}}}

{{{3y/3=6x/3+1/3}}}

{{{y= 2x+1/3}}}

*[invoke equation_parallel_or_perpendicular "parallel", 2, "(1/3)", -1, 4]