Question 398659
The product of two consecutive positive integers is 5 more than their sum. Find the integers.
---
1st: x
2nd: x+1
-----
Equation:
x(x+1) = (x + (x+1) + 5)
----
x^2+x = 2x+6
x^2-x-6 = 0
------
Factor:
(x-3)(x+2) = 0
Positive solution:
x = 3
=====
1st = x = 3
2nd = x+1 = 4
--------------------
Cheers,
Stan H.